Now it's time to tackle the original question. Going from point A to point B, the cheetah traveled at an average rate of 70 mph. Returning to point A, the cheetah traveled at an average rate of 40 mph. Can we say that this cheetah's average rate was 55 mph? a. The average rate for the trip is equal to the total distance traveled divided by the total time traveled. The following equations represent the distance traveled on each leg of the trip. First leg of trip: dan Second leg of trip: d = r22 Write an equation for the average rate for the trip. Remember, the cheetah runs from point A to point B and back to point A. b. The following equation represents the average rate for the trip. Is this equation equivalent to the one you wrote above? Explain why or why not. Average Rate * 2d d d C The following steps show how the equation for the average rate can be transformed so that it is written in terms of only the rates for each leg of the trip. Write an algebraic justification for each step. Think about the number operations and properties that you know Average Rate 2d d d 2d 2d Average Rate = rd rd rd+rd ri 2d Average Rate = rid+rd 2d 2drn 1 rid +rd rd+rd ( ) adri - Average Rate = 2dr 72 277 rid+rzd d(1+r) 7+r, d. Using the equation for average rate above, determine the cheetah's average rate for the entire trip