A rectangle lengths 12m and 17m and is dilated using the dilation (x, y) -> ( 0.4 x, 0.4y). What is the perimeter of the dilated rectangle?

Perimeter of the dilated rectangle = 23.2 m

Step-by-step explanation:

If a point is dilated by a scale factor = k

Coordinates of the image point after dilation will follow the rule,

(x, y) → (kx, ky)

From the given rule,

(x, y) → (0.4x, 0.4y)

Which reveals that the figure has been dilated by a scale factor = 0.4

Length of the rectangle = 12 m

Width of the rectangle = 17 m

If the given rectangle is dilated by a scale factor of 0.4,

Length of the image rectangle = 12 × 0.4 = 4.8 m

Width of the image rectangle = 17 × 0.4 = 6.8 m

Perimeter of a rectangle = 2(length + width)

Therefore, perimeter of the image rectangle = 2(4.8 + 6.8)

                                                                           = 23.2 m

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

hkhkhkhkhkhkhk

step-by-step explanation: