Can someone plz help me with this one problem

(I’M MARKING BRAINLIEST)

(0,0), (1,2), (2,4), (3,6), (4,8), (5,10)

Step-by-step explanation:

Hi again,

Once again, this equation does not have the "b" for y = mx + b. Therefore, this linear graph will run through the origin (0,0).

To find the y coordinates, you can substitute the x value into y = 2x.

For example, if you put in 2  into y = 2x, you would get 4 for the y-coordinate.

Hope this explains the process. Cheers.

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation: