Subtract 2p^2+3q^2-2r^2+5 from 5p^2-4q^2-7r^2-6

3p²-7r²-5r²-11

Step-by-step explanation:

(5p²-4q²-72²-6)

- (2p²+3p²-2r²+5)=

3p²-7r²-5r²-11

see below

Step-by-step explanation:

Let's sim[plify step-by-step.

5p²−4q²−7r²-6−(2p²+3q²−2r²+5)

Distribute the Negative Sign:

=5p²−4q²−7r²−6+−1(2p²+3q²−2r²+5)

=5p²+−4q²+−7r²+−6+−1(2p²)+−1(3q²)+−1(−2r ²)+(−1)(5)

=5p²+−4q²+−7r²+−6+−2p²+−3q²+2r²+−5

Combine Like Terms:

=5p²+−4q²+−7r²+−6+−2p²+−3q²+2r²+−5

=(5p²+−2²)+(−4q²+−3q²)+(−7r²+2r²)+(−6+−5)

=3p²+−7q²+−5r²+−11

=3p²−7q²−5r²−11

94

step-by-step explanation:

average the numbers and use a variable to figure out the minimum to get a 90.

(79+94+91+92+x)/5=90

x = 94

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)