Find the equation of a line that passes through (2,9) and is parallel to the graph of y = 3x + 6. Write the equation in slope-intercept form, if possible.

y = 3x + 3

Step-by-step explanation:

If two lines are parallel to each other, they have the same slope.

The first line is y = 3x + 6. Its slope is 3. A line parallel to this one will also have a slope of 3.

Plug this value (3) into your standard point-slope equation of y = mx + b.

y = 3x + b

To find b, we want to plug in a value that we know is on this line: in this case, it is (2, 9). Plug in the x and y values into the x and y of the standard equation.

9 = 3(2) + b

To find b, multiply the slope and the input of x (2)

9 = 6 + b

Now, subtract 6 from both sides to isolate b.

3 = b

Plug this into your standard equation.

y = 3x + 3

This equation is parallel to your given equation (y = 3x + 6) and contains point (2, 9)

Hope this helps!

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