If 0° SOS 90° and cose 15, what is the value of sin (90° - 9)?
A: 11/15
B: 15/11
C: 15/4
D: 4/15

The answer is 11/15 A

X^2 - 4x +(4/2^2) + y^2 + 8y + (8/2^2) = -4 + (4/2^2) + (8/2^2)(x + 2)^2 + (y + 4)^2 = -4 + 4 + 16your center is (-2, -4) and the radius is the sqrt of -4 + 4 + 16 which is 4