In ΔIJK, the measure of ∠K=90°, IK = 9, JI = 41, and KJ = 40. What ratio represents the sine of ∠I?

The ratio is 40/41
Step-by-step explanation:
In this question, we are to find the ratio that represents sine of angle I
Firstly, let’s consider the diagram of the triangle attached.
When we talk of sine, what we mean is the trigonometric identity which measures the ratio of the opposite to the hypotenuse.
Since the angle we are considering is I, the opposite is 40, while the hypotenuse is 41 ( the longest side of the triangle and the side that faces the angle 90, which is the length JI)
Thus,
mathematically sine I = 40/41