a gift box in the shape of a rectangular prism measures 8in by 8in by 10in. what is the least amount of wrapping paper needed to wrap the gift box? ​

Step-by-step explanation:

The surface area of a rectangular prism is

A=2(xy+xz+yz), where x,y,z are the dimensions, in this case

A=2(8(8)+8(10)+8(10))

A=2(64+80+80)

A=2(224)

A=448in^2

So the minimum amount of wrapping paper is 448in^2

the answer is 13

step-by-step explanation:

5*5=25

12*12=144

25+144=169

169^2=13

you ignore the remainder, therefore the answer is y = x+2

step-by-step explanation:

you have to divide the denominator by the numerator. you can use synthetic division or long division.

[-5] .     1 .     7 .     11

x + 2 + 1/x+5