Find the surface area of a cylinder with the height of 10 inches and a base diameter of 6 in ​

339.24

Step-by-step explanation:

To find the surface area, you will need to the the area of the base of the cylinder. To do that, use the formula A=pi (r)^2

The radius is half the diameter do r=3

3.14(3)^2 should give you about 28.27.

This is the area of the top and bottom of the cylinder.

Now, do 28.27x10=282.7 to find the height surface area.

282.7+28.27+28.27=Surface area.

SA= about 339.24

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.