Una fábrica de autopartes logra una producción con sólo 3% de piezas defectuosas. Realiza un diagrama de árbol para determinar la probabilidad de que, al tomar aleatoriamente dos piezas: a) Ambas estén defectuosas.
b) Ninguna esté defectuosa.
c) Sólo una esté defectuosa.

Answer: the correct answer is 10step-by-step explanation: let the number be n, then the expression becomes,then“twelve more than the quotient of a number and two, decreased by four” iswhen n=4,we substitute 4 whetever we see n to get,we simplify to obtain,we further simplify to get,therefore the correct answer is c.

The answer is 270 cars.you can do this by making a proportional relationship. for instance, 200 is the whole we are using, so on a “number line” 200 would be over 100%. now, since he sells 35% more, add 35% to 100% to get 135% on the other side of the “number line” on the bottom half, leaving the top half empty.cross multiply 200 by 135 then divide by 100 to get your answer. i hope this , if it did, , if you don’t mind, giving me brainiest! 200/100% } 200 • 135 /100 ? /135%

Well is there a picture