15. Find the force on an electron crossing a uniform magnetic field of intensity 0.5 T WILII velocity of 106 ms-1. The charge carried by the electron is -1.6 x 10-19C.​

F = 8.48 x N

Step-by-step explanation:

The force on an electron in a magnetic field can be determined by;

F = qvB Sin θ

where: e is the electron, v is its velocity, B is the measure of the magnetic field, and θ is the angle of its path.

Thus,

q = -1.6 x C

v = 106 m/s

B = 0.5 T

θ =

So that,

F = 1.6 x x 106 x 0.5

  = 8.48 x N

The force on the electron crossing the uniform magnetic field is 8.48 x N.

4+n=5

step-by-step explanation:

this is because the four is four hours and the n represents the 1 extra hour over the weekend.

b= i'm srry i don't know that one.

4+n=5 n=1 because if vernon plays 5 hours a week then 4+1=5 hours.

hope this : )

the discriminant is 64 + 4*1*12 = 112

this is prime.

step-by-step explanation: