I NEED HELP ASAPPP The UAV is flying at a speed of 13 meters per second in the direction toward
the fire. Suppose the altitude of the UAV is now 800 meters. The new position
is reprented at F in the figure.
Ewn<>
30°
А
D
From its position at point F, how many minutes, to the nearest tenth of a
minute, will it take the UAV to be directly over the fire?
A 0.6
1.2
1.8
2.0
C
D

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west

open side up . . 1/50 . . 2%

closed side up . . 5/50 . . 10%

landed on side . . 44/50 . . 88%