PLEASE HELP -x² + 11, when x > -4
and
3(square root) x+5, when x < (or equal to) -4

nabirayu gru'dyu vozdka chtolby bol'she ne dyshad vso chto ranit zabivayu chtolby ranit sya opyat

Step-by-step explanation:

razcharovad menya razcharovad menya razcharovad menya razcharovad menya

moye imya tvoy strakh krovotochit na gubak

moye imya tvoy strakh krovotochit na gubak

moye imya tvoy strakh krovotochit na gubak

moye imya tvoy strakh krovotochit na gubak

moye imya tvoy strakh krovotochit na gubak

moye imya tvoy strakh krovotochit na gubak

moye imya tvoy strakh krovotochit na gubak

moye imya tvoy strakh krovotochit na gubak

idk

step-by-step explanation:

idk

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine