Which type of sample do you believe would be the best to use if you are trying to get a random sample: A convenience sample, a voluntary response, or asking every 4th person on a list? Why?

Step-by-step explanation:

Integer: An integer is any whole number. This includes positive whole numbers (like 1, 2 and 3), negative whole numbers (like -1, -2 and -3), and zero (0).

Positive Integer: A positive integer is any whole number greater than 0 (like 1, 2, 3 and so on).

Negative Integer: A negative integer is any whole number less than 0 (like -1, -2, -3 and so on). Negative integers are preceded by the symbol "-" so that they can be distinguished from positive integers

X: X is the symbol we use as a variable, or placeholder for our solution. In the case of inequalities, X usually represents a series of numbers rather than a single number

<: This symbol means "less than" and is used to indicate that the number to its left (the pointy side) is less than the number to its right (the open side).

>: This symbol means "greater than" and is used to indicate that the number to its left (the open side) is greater than the number to its right (the pointy side).

≤: This symbol means "less than or equal to" and is used to indicate that the number to its left (the pointy side) is less than or equal to the number to its right (the open side).

≥: This symbol means "greater than or equal to" and is used to indicate that the number to its left (the open side) is greater than or equal to the number to its right (the pointy side).

How to Find All of the Integers That Satisfy an Inequality

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

answer: 42

use a calculator to find that 845/73 = 11.575

the whole part of the answer is 11. multiply this by 73 to get 11*73 = 803.

subtract that result from 845 to get 845 - 803 = 42