![\displaystyle\sqrt[3]{1000^2}=(1000^2)^{\frac{1}{3}}=1000^{\frac{2}{3}}=(10^3)^{\frac{2}{3}}=10^2=\boxed{100}](/tpl/images/1194/3720/44af7.png)
![\displaystyle\sqrt[3]{1000^2}=\sqrt[3]{(10^3)^2}=\sqrt[3]{(10^2)^3}=10^2=100](/tpl/images/1194/3720/1b685.png)
Can someone help me with this? I don't understand?
How do you do the whole process? I need so...
Mathematics, 17.03.2021 23:40 sama3638
Can someone help me with this? I don't understand?
![\sqrt[3]{1000 {}^{2} }](/tpl/images/2224/6052/08d2d.png)
How do you do the whole process? I need some explanation...
Answers: 1
Another question on Mathematics
Mathematics, 21.06.2019 17:00
Find the area of a parallelogram with the given vertices. p(-2, -5), q(9, -5), r(1, 5), s(12, 5)
Answers: 1
Mathematics, 21.06.2019 23:00
Which geometric principle is used to justify the construction below?
Answers: 1
You know the right answer?
Questions
Mathematics, 22.01.2021 20:00
Biology, 22.01.2021 20:00
Chemistry, 22.01.2021 20:00
Mathematics, 22.01.2021 20:00
Spanish, 22.01.2021 20:00
Mathematics, 22.01.2021 20:00
Mathematics, 22.01.2021 20:00
English, 22.01.2021 20:00
Spanish, 22.01.2021 20:00
Geography, 22.01.2021 20:00
Chemistry, 22.01.2021 20:00
