Square OPQR is inscribed in triangle ABC. The areas of △AOR, △BOP, △CRQ are 1, 3, and 1, respectively. What is the area of square OPQR?

9 units²

Step-by-step explanation:

We know that ΔCRQ and ΔBOP are right triangles because RQ and OP are perpendicular to CB.

ΔAOR must also be a right triangle because ∠AOR = ∠OBP and ∠ARO = ∠RCQ.

Because of the Angle-Angle-Angle theorem, we know that ΔAOR ≅ ΔBOP ≅ ΔCRQ.

AR/AO = OP/PB

3(1/2)(AR)(AO) = (1/2)(OP)(PB)

PB = 6, OP = 3

3 x 3 = 9 units²

t = 3

step-by-step explanation:

put t = 3 in this expression :

(3²-1)(3²-2)(3² - 3)(3² - 4) = 8×7×6×5 = 56×30 = 1680

it would be:

c.parallelogram.