subject
Mathematics, 17.03.2021 23:50 cdraytonn

How would you solve this?


How would you solve this?

ansver
Answers: 2

Another question on Mathematics

question
Mathematics, 21.06.2019 21:00
Which line is parallel to the line that passes through the points (2, –5) and (–4, 1) a. y=-x+5 b. y=-2/3x+3 c. y=2/3x-2 d. y=x+5
Answers: 2
question
Mathematics, 21.06.2019 21:50
6x + 3y = -6 2x + y = -2 a. x = 0, y = -2 b. infinite solutions c. x = -1, y = 0 d. no solution
Answers: 1
question
Mathematics, 22.06.2019 01:00
For every corresponding pair of cross sections, the area of the cross section of a sphere with radius r is equal to the area of the cross section of a cylinder with radius and height 2r minus the volume of two cones, each with a radius and height of r. a cross section of the sphere is and a cross section of the cylinder minus the cones, taken parallel to the base of cylinder, is the volume of the cylinder with radius r and height 2r is and the volume of each cone with radius r and height r is 1/3 pie r^3. so the volume of the cylinder minus the two cones is therefore, the volume of the cylinder is 4/3pie r^3 by cavalieri's principle. (fill in options are: r/2- r- 2r- an annulus- a circle -1/3pier^3- 2/3pier^3- 4/3pier^3- 5/3pier^3- 2pier^3- 4pier^3)
Answers: 3
question
Mathematics, 22.06.2019 02:00
The table below shows the approximate masses of a dust particle and a grain of pollen. dust particle 0.000000778 g grain of pollen 0.00000000155 g the mass of a dust particle can be estimated and written in the form a × 10^b, where a = 8 and b = the mass of a grain of pollen can be estimated and written in the form a × 10^b, where a = 2 and b = based on the estimates, the mass of a dust particle is approximately blank times larger than the mass of a grain of pollen.
Answers: 1
You know the right answer?
How would you solve this?
...
Questions
question
Mathematics, 10.12.2020 01:20
question
Biology, 10.12.2020 01:20
question
Arts, 10.12.2020 01:20
question
Mathematics, 10.12.2020 01:20
Questions on the website: 13722367