Find two integers whose sum is 20 and product is 99

11 and 9

Step-by-step explanation:

X+Y=20

X*Y=99

Y=20-X

X*(20-X)=99

20X-X^2=99

20X-X^2–99=0

-(X - 11) (X - 9) = 0

Two solutions

X-11=0, X=11

X-9=0, X=9

Y=20-X, so if X is 9, Y is 11

Y=20-X, so if X is 11, Y is 9

The two numbers are 11 and 9

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3

soo this can be solve by using the formula:

f = p( 1 + i)^ n

where f is the future profit

p is the initial profit

i is the percent increase

n is the number of years

a . f = 30000 ( 1.05)^n

b. f = 30000 ( 1.05)^15

f = $62,368