Let ff be a differentiable function with f(-1)=3f(−1)=3 and f'(-1)=-5.f ′
(−1)=−5. Let the function g(x)=x^2f(x).g(x)=x
2
f(x). Write the equation of the line tangent to the graph of gg at the point where x=-1.x=−1.

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3

15 units use socratic

step-by-step explanation: 15 units