Which set of ordered pairs satisfies an inverse variation?
. (6, 3) and (8,4)
H. (4, -2) and (-5, 10)
. (2, -3) and (4, 5)
J. (2,6) and (-3,-4)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.

answer: 1 box of pens at the store ? ? pens in the box

step-by-step explanation:

we are given polynomial 2x^2 +4x +7.

we need to determine the number of roots of the given polynomial using the fundamental theorem of algebra.

a) for the given polynomial 2x^2+4x+7, we have degree =2.

b) let us find the roots of the given polynomial.

2x^2+4x+7= 0