population of a small town of $10,800 2002 the population has decreased at a rate of 2.5% each year write an exponential function to model the situation then find the population of the town of 2020​

The population of the town of 2020 is approximately 6847

Step-by-step explanation:

The given population of the small town is 2002, P₀ = 10,800

The annual percentage decrease in the population, r = 2.5%

The date at which the new population,'P', is required = 2020

Therefore;

The number of years over which the population changes, 't', is given as follows;

t = 2020 - 2002 = 18

The number of years over which the population changes, t = 18 years

Given that the population is decreasing, we get;

The general formula for exponential decay is given as follows;

Therefore, the population, 'P', of the town of 2020 which is in t = 18 years, is given as follows;

Given that the population is given in whole numbers, we round down to the nearest whole number population of people as follows;

The population of the town of 2020, P ≈ 6847.

6 hours 48 min

step-by-step explanation:

68÷5=13.6

13.6×30=408min=6 hours 48 min.

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answer: howdy

step-by-step explanation: