Can someone
Please
Help me

First let's calculate the area of the bottom part

diameter is 34 m

so the radius (r) is 1/2 * 34 m = 17 m

bottom part is 1/2 of a circle

circle surface area formula is πr²

so surface area of our bottom part is 1/2 * πr²

1/2 * πr² = 1/2 * 3,14 * 17² = 453,73

so it's 453,73 m²

Triangle part consists of 2 smaller rectangular triangles

surface area for rectangular triangle is 1/2 * a * h

in our case a = r = 17 m and h = 30m

so one smaller rectangular triangle is 1/2 * r * h = 1/2 * 17 * 30 = 255

so it's 255 m²

and because our entire triangle part consists of 2 smaller rectangular triangles it's area is 2 * 255 m² = 510 m²

Surface area of the entire figure is a sum of 510 m² and  453,73 m²

510 m² +  453,73 m² =  963,73 m²

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value