Give triangle ABC with coordinates A(3, 8), B(9,0) and C(5,2). How can you prove that triangle ABC is isosceles? Show your work.

The distances AB and BC are

√

52

and therefore isosceles.

Explanation:

If we label them A(13,-2) B(9-8) and C(5-2)

The distance between A and B:13⇒9=4−2⇒−8=42+62=52 so the distance is √52

The distance between B and c:9⇒5=4−8⇒−2=642+62=52

the distance is

√

52

The distance between A and C is 8 as they are both on -2 for

y

The distances AB and BC are

√

52

and therefore isosceles.Step-by-step explanation:

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step-by-step explanation:

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116