Since 2007, a psychological association has supported an annual nationwide survey to examine stress across the United States. One year, a total of 760 millennials (18- to 33-year-olds) were asked to indicate their average stress level (on a 10-point scale) during a month. The mean score was 5.5. Assume that the population standard deviation is 2.8. Give the margin of error for a 95% confidence interval. (Enter your answer to three decimal places.)

The margin of error for a 95% confidence interval is 0.199.

Step-by-step explanation:

We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of .

That is z with a pvalue of , so Z = 1.96.

Now, find the margin of error M as such

In which is the standard deviation of the population and n is the size of the sample.

Assume that the population standard deviation is 2.8.

This means that

760 millennials (18- to 33-year-olds)

This means that

Give the margin of error for a 95% confidence interval.

The margin of error for a 95% confidence interval is 0.199.

the answer is a.

step-by-step explanation:

in three games of golf, alex shot two under par four times.

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)