P 1. Con relación a la figura nombre lo siguiente:
a) Dos ángulos rectos.
b) Dos ángulos agudos.
c) Dos ángulos suplementarios.
d) Dos ángulos complementarios
e) Dos rectas paralelas.
f) Dos rectas perpendiculares
g) Una recta transversal.
S
R
D
2. Observa la figura y determine lo que se pide.
a) Tres ángulos agudos.
b) dos ángulos obtusos.
c) dos ángulos suplementarios
d) un ángulo recto.
e) dos ángulos opuestos por el vértice.
f) Dos ángulos complementarios.
g) Dos ángulos alternos internos.
h) dos pares de ángulos correspondientes.
Ayudaa​

Answer is in the photo. I couldn't attach it here, but uploaded it to a file hosting. link below! Good Luck!

cutt.ly/4zZs6GM

you can first factor out the n to get n(1+5). we know that 1+5 is 6, so we just have 6n.

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.