The height of the triangle is 3 meters longer than twice its base. Find the base and height if the area is 8 square meters. Round to the nearest hundreth.

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Step-by-step explanation:

Let b represent the base of the triangle in meters. Then the height is ...

  h = 3 +2b

and the area is ...

  A = 1/2bh

  8 = 1/2(b)(3 +2b)

  16 = 3b +2b^2 . . . . . . . multiply by 2 and eliminate parentheses

  2(b^2 +3/2b + (9/16)) = 16 + 9/8 . . . . . . complete the square

  2(b +3/4)^2 = 17.125

  (b +3/4)^2 = 8.5625 . . . . . divide by 2

  b + 0.75 = √8.5625 ≈ 2.9262

  b = -0.75 +2.9262 = 2.1762

  h = 3 +2b = 7.3523

The base is about 2.18 meters and the height is about 7.35 meters.

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below:

solve systems of equations by graphing. a system of linear equations contains two or more equations e.g. y=0.5x+2 and y=x-2. the solution of such a system is the ordered pair that is a solution to both equations. to solve a system of linear equations graphically we graph both equations in the same coordinate system