In ΔOPQ, o = 58 cm, q = 13 cm and ∠Q=52°. Find all possible values of ∠O, to the nearest degree.

There is no possible triangles

Step-by-step explanation:

\frac{\sin A}{a}=\frac{\sin B}{b}

a

sinA

​  

=  

b

sinB

​  

From the reference sheet (reciprocal version).

\frac{\sin O}{58}=\frac{\sin 52}{13}

58

sinO

​  

=  

13

sin52

​  

Plug in values.

\sin O=\frac{58\sin 52}{13}\approx 3.5157403

sinO=  

13

58sin52

​  

≈3.5157403O=\sin^{-1}(3.5157403)= \text{ERROR}

O=sin  

−1

(3.5157403)=ERROR

Sine cannot be greater than 1.

{No Possible Triangles}

No Possible Triangles

{}

{}

what are you trying to solve here

step-by-step explanation: