Graph f(x)=4x2+20x+16​

f=2 x=2   i think srry if im wrong

Step-by-step explanation:

Direction: Opens Up

Vertex:  

(

−

5

2

,

−

49

)

Focus:  

(

−

5

2

,

−

783

16

)

Axis of Symmetry:  

x

=

−

5

2

Directrix:  

y

=

−

785

16

Select a few  

x

values, and plug them into the equation to find the corresponding  

y

values. The  

x

values should be selected around the vertex.

Tap for more steps...

x

y

−

4

−

40

−

3

−

48

−

5

2

−

49

−

1

−

40

0

−

24

Graph the parabola using its properties and the selected points.

Direction: Opens Up

Vertex:  

(

−

5

2

,

−

49

)

Focus:  

(

−

5

2

,

−

783

16

)

Axis of Symmetry:  

x

=

−

5

2

Directrix:  

y

=

−

785

16

x

y

−

4

−

40

−

3

−

48

−

5

2

−

49

−

1

−

40

0

−

24

image of graph

answer: sine

step-by-step explanation:

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.