25^x = 125^(x+3)

a. x = -10
b. x = -9
c. x = -3
d. x = 3

25^x = 125^(x+3)

5^2x=5^3(x+3)

we get

2x=3(x+3)

2x=3x+9

-9=3x-2x

x=-9

option

b. x = -9 is right answer.

Create equivalent expressions in the equation that all have equal bases, then solve for

your answer is -9

step-by-step explanation:

sry but any answer choices

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.