Encontrar la Esperanza Matemática y Desviación Estándar del número de imperfecciones (y) en pizarra acrílica. (2 puntos) y 0 1 2 3 P(y) 1/8 ¼ ½ 1/8

Responder:

1,625; 0.8569

Explicación paso a paso:

y ___0 1 2 3

P (y) _1 / 8 ___ ¼ ___ ½ 1/8

Valor esperado (E (x)): Σx * p (x)

= (0 * (1/8)) + (1 * (1/4)) + (2 * (1/2)) + (3 * (1/8)) = 1,625

La desviación estándar = sqrt (Var (x))

Var (X) = Σx²p (x) * E (x) ²

Var (X) = [(0 ^ 2 * (1/8)) + (1 ^ 2 * (1/4)) + (2 ^ 2 * (1/2)) + (3 ^ 2 * (1 / 8))] - 1.625²

Var (X) = (0 * (1/8)) + (1 * (1/4)) + (4 * (1/2)) + (9 * (1/8)) - 1.625 ^ 2

= 3.375 - 2.640625

= 0,734375

Desviación estándar = Sqrt (0,734375) = 0,8569

you are uyytr tyy

step-by-step explanation:

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)