Crime 2: Some thief has taken a necklace from old Mrs. Hexagon. The culprit ran
off very fast, but not before some bystanders got a look at the culprit.

Witness 1 (Mrs. Hexagon) -- "It all happened so fast! All I can tell you is
that the thief had congruent diagonals."
Witness 2 -- "As this individual was fleeing the scene of the crime, I saw a
pair of parallel sides. I did not get a look at the other pair of sides, so I'm
not sure if there were two pairs or not."
Witness 3 -- "I did not notice if the sides were parallel or not, but I saw a
pair of opposite sides that were definitely not congruent."

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation:

answer: bea's uncle is 25 years old.

step-by-step explanation:

given the equation , we can say that the variable "x" represents the age of bea's uncle. then to find his age, we need to solve for "x":

we must add 15 to both sides of the equation:

now we need to divide both sides of the equation by 3:

therefore, we can conclude that bea's uncle is 25 years old.

i honestly dont know

the transitive property of equality.

step-by-step explanation:

the correct answer is:

the transitive property of equality.

explanation:

we know that  ∠bcd is congruent to  ∠pbc. we also know that  ∠pbc is congruent to  ∠bad.

we can substitute  ∠bad for  ∠pbc in the first angle congruence statement to give us:

∠bcd is congruent to  ∠bad.

algebraically, the transitive property states if a=b and b=c, then a=c. it basically allows us to substitute equal values. since that is what we did, this is the transitive property.

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