Construct a quadrilateral ABCD , Where AB- 6cm , CD- 6.5cm , LL- 70°, LA- 95°​

Solution:

Given : A quadrilateral A B CD, in which, AB=5  cm, BC = 6 cm, CD =6.5 cm , angle B= 105° and angle C = 75

Steps of construction

(1) Draw a line segment B C of length 6 cm.

(2) At Point B and C , with the help of Compass draw angle of  105° and 75° respectively.Name the rays as C M and B Z respectively.

105°→Draw an angle of 120° and 90° and draw angle bisector between 90° and 120°.

75°→Draw angle bisector of 60° and 90°.

(3) From C , mark an arc at a distance of 6.5 cm on ray CM.You will get point D.

(4) From B , mark an arc at a distance of 5 cm on ray B Z.You will get point A.

(5) Join A and D.

This is required trapezoid A B CD.

here, AB ║CD→→∠B+∠C=180°[If sum of interior angles on the same side of transversal is supplementary then lines are parallel.]

answer: 30

step-by-step explanation: its 30 because im a basketball player and stephen curry hits most of his shots so if you put 30 you might make the shot goodluck