Im trying to do IXL and I dont understand the way my teacher teaches (ironic right?) Can you please help?
the points (1,k) and (0,4) fall on a line with a slope of -9. What is the value of k?
If its not right im gonna report you

k=-5

Step-by-step explanation:

equation for slope

y2-y1

x2-x1

4-k/0-1

4-k/-1

4-(-5)/-1

9/-1=-9

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

trapezoid

step-by-step explanation:

first i plotted all my points on a grid graph

i made sure all of them were in the correct quadrant

then i saw it was a trapezoid or a quadrilateral