A new car is purchased for 20000 dollars. The value of the car depreciates at 11% per year. To the nearest tenth of a year, how long will it be until the value of the car is 5700 dollars?

0.285

Step-by-step explanation:

first we will have to find our equation:

20,000(p = principal) x r (rate) = 5,700

20,000 × (r) = 5,700

since we are multiplying, we would divide the equation:

5,700 / 20,000

this would then equal to our answer 0.285

to check your answer we can do,

0.285 x 20,000

which would give use our depreciated value of $5,700.

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

amount of oatypop that contains the prize = 40%

amount   of oatypop which doesn't contain the prize = (100-40)=60%

probability that hannah will win a prize

    = s +f s +f f s+ff   f s+ff f f s+ infinity.where f= failure,s= success

=   or 60%

probability that hannah only has to buy 3 or less boxes before getting a prize= (s) and ( f s) and (ff s) and (f f f s)

        = = 87.04 %  

step-by-step explanation: