Write an equation in slope-intercept form (y=mx+b) for the line that has a slope of 12 and passes through the point (3, 20).

y= 12x-16

Step-by-step explanation: Given that you have a slope of 12 and a point of (3, 20), you are most obligated to using the Slope-Intercept form, or y=mx+b.

What this allows you to find is the y-intercept if your line has one. You take your point, (3,20), and you insert the values at the appropriate places. You should now have 20=12(3)+b. You will then solve for b by multiplying 12 and 3 to get 36 and subtract that from both sides of the equal sign. You should have 20-36=b. 20-36 is -16, which is your y-intercept.

Now you know all your needed values, you would write the Slope-Intercept form without the values for y and x, to represent your equation.

Since 12 is your slope, it will be 'm' and -16 will be 'b'.

You will end with y = 12x - 16.

answer: 1) twenty-seven times y

              2) twenty-seven multiplied by y

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !