Write the equation of a line parallel to the line 2x + y = 3 that passes through the point (2,6)

Answer (assuming it can be in slope-intercept form):

Step-by-step explanation:

1) First, we need to find the slope of the given equation. To do that easily, convert it to slope-intercept form, represented by the formula  . Isolate y:

The number in place of , or the coefficient of the x-term, represents the slope of the equation. So, the slope of the given equation is -2.

Lines that are parallel share the same slope. So, the slope of the new equation will be -2 as well.  

2) Now, remember that the slope-intercept form is represented by the formula . In order to write an equation of a line using that formula, we need to substitute values for and . We know is the slope, so we already know what that equals. Now, we just need to find .

To do that, substitute -2 for in the slope-intercept formula. Additionally, substitute the x and y values of the point (2,6) for the x and y in the formula as well. This sets up the equation so that we can isolate and find its values:  

So, = 10.

3) Substitute values for and into the slope-intercept formula to write the slope-intercept form of the line:

a. 32 degrees

step-by-step explanation:

here we have to use the rule.

m∠e = 1/2 (major arc - minor arc)

m∠e = 1/2 (212 - 148)

m∠e = 1/2 (64)

m∠e = 32 degrees

answer: a. 32 degrees

you

b is the correct answer