For time t≥0, the velocity of a particle moving along the x-axis is given by v(t)=cos(8e^−0.2t). The initial position of the particle at time t=0 is x=2.5. What is the displacement of the particle from time t=0 to time t=15?

i dont know

Step-by-step explanation:

it is true

step-by-step explanation:

all the combinations add up i used   calculator

answer: 4 meters

step-by-step explanation: to you understand 2/3 better you can do 1 divided by 3 = . then multiply that by the 2 which is .66666666666666667 then you would do 6 x .66666666666666667 which is 4.      

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