Imagine standing several feet away from 3 equally-sized garbage cans (A, B, and C) that are all pushed together such that they are all touching each other. Imagine also, that you want to throw 2 wadded up pieces of paper into the garbage cans, but the aerodynamics of the paper balls are such that the paper curves unpredictably in the air as it travels to the cans. Repeated testing concludes that the paper lands in any one of the cans completely randomly. What is the probability that both paper balls will land in can B

the first dot plot best represents the data

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1/3 + 1/3 ≠ 2/6 because 1/3 alone = 2/6  

step by step explanation:

1/3 + 1/3 = 2/3       2/3=4/6

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step-by-step explanation:

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

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