Consider function h. (3r 4,
ぶく0
hil) = 212 – 31 + 10, 0 2",
What are the values of the function when I = 0 and when I = 47
h(0) =
h(4)

hi,

i'm 75% sure the answer is 1,1 to both lines.

have a great day

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)