The point-slope form of the equation of a line that passes through points (8,4) and (0,2) is y-4=1/4(x-8). what is the slope-intercept form of the equation for this line ?
A = y=1/4x-12
B = y=1/4x-4
C = y=1/4x+2
D = y=1/4x+6

What are the coordinates of the hole in the graph of the function f(x) ? f(x)=x2−9x−3 enter your answer in the boxes.

Which simplifys to a+ b? a-(1-b)+1 -(1-a)-b+1 (a--1) -1)+1

Prove (a) cosh2(x) − sinh2(x) = 1 and (b) 1 − tanh 2(x) = sech 2(x). solution (a) cosh2(x) − sinh2(x) = ex + e−x 2 2 − 2 = e2x + 2 + e−2x 4 − = 4 = . (b) we start with the identity proved in part (a): cosh2(x) − sinh2(x) = 1. if we divide both sides by cosh2(x), we get 1 − sinh2(x) cosh2(x) = 1 or 1 − tanh 2(x) = .