In a javelin throw competition, five athletics score 56, 58, 63, 57 and 61 meters. What are their Mean and Median?

Mean = 59

Median = 58

Step-by-step explanation:

Given the data for a Javelin throw :

56, 58, 63, 57 61 meters

Reordering the data: 56, 57, 58, 61, 63

Mean, m = Σx / n

n = sample size = 5

m = (56 + 57 + 58 + 61 + 63) / 5

m = 295 / 5

m = 59

The median : 1/2 (n+1)th term

1/2(5 +1) the term

1/2(6) = 3rd term

Median value = 58

there are 70 more legs than eyes at the dog show (196 – 126 = 70). dogs have two more legs than eyes, and humans have the same number of legs as eyes. thus 70 is twice the number of dogs at the show, so the number of dogs is half of 70, which is 35. to get the number of humans, subtract 35 from 63: 63 – 35 = 28.

step-by-step explanation: