What is the sum of the interior angles of a regular polygon with 42 sides?

42

Step-by-step explanation:

A regular polygon with 42 sides where the length of each side is 2 units. The units may either be inches or cm or km or miles: any unit of length.

You are given a Regular Polygon with 42 sides. What are the interior angles and exterior angles?

If the length of each side is 2 units, what is the perimeter, area, circum-radius and in-radius of the polygon?

n = 42

Perimeter of a polygon with 42 sides = (side length) x 42 = 84 units

Area of a polygon with 42 sides = (n x Side2 x cot (Π/n))/4 = (n x 22 x cot (Π/42))/4 = 560.45 square units

Sum of the interior angles of a polygon with 42 sides =  (n-2) x 180 degrees =  (42-2) x 180 degrees = 7200 degrees

Interior Angle of a polygon with 42 sides = (n-2) x 180/n degrees = (42-2) x 180/42 degrees = 171.42 degrees

Exterior angle of a polygon with 42 sides = 180 - Interior Angle = 180 - 171.42 = 8.57 degrees

Inradius = Radius of In-circle = (side length) x cot (Π/42) = 2 x cot 4 = 26.68 units

Circumradius = Radius of Circum-circle = (side length) x cosec (Π/42) = 2 x cosec 4 degrees = 26.76 units

Symmetry Group = D42  42 rotational symmetries and 42 reflection symmetries. The "D" stands for di-hedral.

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hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~