In ΔUVW, w = 840 cm, u = 350 cm and ∠V=63°. Find the area of ΔUVW, to the nearest square centimeter.

i think is 3 and 6. this took me 10 min to think.hope to and hope that my answer is brainliest.(follow me )

the answer will be b x² +x-1

step-by-step explanation:

answer: the correct option is d.

explanation:

it is given that the triangle j'k'l' shown on the grid below is a dilation of triangle jkl using the origin as the center of dilation.

from the given graph it is noticed that k(4,8) and k'(2,4). let origin is defined by o and scale factor is defined by k, then

    (1)

distance formula,

put these values in equation (1).

therefore scale factor is     and option d is correct.