best answer get brainlest Can you prove the triangles below are congruent? Explain why or why not.

This is kinda confusing but I would say no

Step-by-step explanation: Because they would be congruent if the little line in JKD is in the middle of JK  instead of KD.

The traingles are not congruent.

Step-by-step explanation:

ang A=ang J

ang L=ang K

LA=KD

So, u must have thaught that the triangles are congruent by ASA. But it's not true.

The Angle-Side-Angle criterion states that the two triangles can only be congruent if two angles and the included side of one triangle are equal to the corresponding two angles and the included side of the other triangle.

But here, the LA is the included side but KD is not. In order to be congruent, LA must congruent to KJ of ∆JKD.

starting with:    

5 + x - 12 = 2x - 7   

5 + x - 12 - x = 2x - 7 - x (subtract x from both sides)   

5 - 12 = x - 7 (combine and cancel x's from both sides)   

5 - 12 + 7 = x - 7 + 7 (add 7 to both sides)   

0 = x (add numbers together on both sides)       

so in order for the equation to be true, x must be 0.   

trying x = -0.5   

5 + x - 12 = 2x - 7 (original equation)   

5 + -0.5 - 12 = 2(-0.5) - 7 (plug in value of x)   

5 + -0.5 - 12 = -1 - 7 (did multiplication)   

-7.5 = -8 (did addition on both sides)       

since -7.5 is obviously not equal to -8, the value of -0.5 for x is wrong.   

trying x = 0   

5 + x - 12 = 2x - 7 (original equation)   

5 + 0 - 12 = 2(0) - 7 (plug in value of x)   

5 + 0 - 12 = 0 - 7 (did multiplication)   

-7 = -7 (did addition on both sides)       

since -7 equals -7, that demonstrates that the value of 0 for x is correct.   

trying x = 1   

5 + x - 12 = 2x - 7 (original equation)   

5 + 1 - 12 = 2(1) - 7 (plug in value of x)   

5 + 1 - 12 = 2 - 7 (did multiplication)   

-6 = -5 (did addition on both sides)       

since -6 is obviously not equal to -5, the value of 1 for x is wrong.

there would only be 50 odd numbers between 1 and 100 so therefor there would be 50 even so that would only be 50 odd numbers.