URGENT, PLEASE HELP A carpenter built three bookcases, A, B, and C, to stand next to each other along a wall. The total length of the wall is
450 centimeters. The carpenter will build two more bookcases, D and E, along the same wall. these two bookcases
will have equal widths. The widths of bookcases A, B, and C are shown: What is the width, n, for bookcases D and E.
Bookcases (not drawn to scale)
A
D
E
B
90
C
110
100
n
n

The width of bookcase D is 61 cm

The width of bookcase E is 61 cm

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Sum the widths of the three bookcases A, B and C

step 2

Subtract the sum of the three bookcases A,B and C from the total length of the wall

step 3

Divide that answer in step 2 by 2, and that will let you know the widths of D and E, because they may have equal widths

therefore

The width of bookcase D is 61 cm

The width of bookcase E is 61 cm

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !