Pls pls help A rectangular piece of paper with length 39 cm and width 20 cm has two semicircles cut out of it, as shown below. Find the area of the paper that remains. Use the value 3.14 for π , and do not round your answer. Be sure to include the correct unit in your answer.

my butt

Step-by-step explanation:

The area of the piece of paper is 466 cm²

Step-by-step explanation:

First you would want to find the area of the rectangle

39x20=780 cm²

Both semi-circles are the same, so you can just find the area of the whole circle

The diameter is 20 cm so you would use 10 as the radius

A=πr²

A=3.14x10²

A=3.14x100

A=314

Then you have to subtract the area of the circle from the area of the rectangle.

780-314=466

The area of the piece of paper is 466 cm²

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3

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step-by-step explanation: