What is the initial value in the equation f(x) = 350(1 - 0.12)^x? *

Given:

The function is:

To find:

The initial value of the function.

Solution:

We have,

The value of the function at x=0 is called the initial value of the function.

For x=0, we get

Clearly 0.88 is a non zero number and zero to the power of a non zero number is always 1.

Therefore, the initial value of the function is 350.

b. y = 4x - 2

step-by-step explanation:

to find a parallel equation to an equation, make sure both equations have the same slope but different y-intercepts.

y = 4x + 1

4 = slope

1 = y-intercept

y = 4x - 2

4 = slope

-2 = y-intercept

they both have the same slope but different y-intercepts, so, b. is the correct answer.

and to check your work, you can graph both equations. : )

#12 the answer is the third option