The number A2...2B has 2009 digits (all digits standing between A and B are twos). This number is divisible by 36. Find the digits A and B if we know that B is greater than 5.

ummm

Step-by-step explanation:

A=6

B=8

Step-by-step explanation:

36=9×4

so lat two digits should be divisible by 4

so they are 20,24,28

so B can be 0,2,8

but B>5

so B=8

now the sum of digits should be divisible by 9

8+2+0+...+0+2+A=12+A

if A=6

then 12+6=18 which is divisib;e by 9

last option

step-by-step explanation:

given that δdef is right and isoceles,

assuming that side df is the hypotenuse means that de an ef are the other 2 sides that intersect at 90° and are of equal length.

because they are of equal length, we can say that they are congruent

because they intersect at 90°, their slopes must be opposite reciprocals.

only the last option satisfies these conditions.