According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select four peanut M&M’s from an extra-large bag of the candies. (Round all probabilities below to four decimal places; i. e. your answer should look like 0.1234, not 0.1234444 or 12.34%.) Compute the probability that exactly two of the four M&M’s are brown.

Compute the probability that two or three of the four M&M’s are brown.

Compute the probability that at most two of the four M&M’s are brown.

Compute the probability that at least two of the four M&M’s are brown.

If you repeatedly select random samples of four peanut M&M’s, on average how many do you expect to be brown? (Round your answer to two decimal places.) brown M&M’s

With what standard deviation? (Round your answer to two decimal places.)
brown M&M’s

Ateacher noticed 5/8 of the students were wearing either blue shorts or white shorts. write two different ways this could be done.

The table shows the relationship between the number of cups of cereal and the number of cups of raisins in a cereal bar recipe: number of cups of cereal number of cups of raisins 8 2 12 3 16 4 molly plotted an equivalent ratio as shown on the grid below: a graph is shown. the title of the graph is cereal bars. the horizontal axis label is cereal in cups. the x-axis values are 0, 20, 40, 60, 80,100. the vertical axis label is raisins in cups. the y-axis values are 0, 10, 20, 30, 40, 50. a point is plotted on the ordered pair 40,20. which of these explains why the point molly plotted is incorrect? (a) if the number of cups of cereal is 40, then the number of cups of raisins will be10. (b)if the number of cups of raisins is 40, then the number of cups of cereal will be10. (c) if the number of cups of cereal is 40, then the number of cups of raisins will be 80. (d) if the number of cups of raisins is 40, then the number of cups of cereal will be 80.

Prove (a) cosh2(x) − sinh2(x) = 1 and (b) 1 − tanh 2(x) = sech 2(x). solution (a) cosh2(x) − sinh2(x) = ex + e−x 2 2 − 2 = e2x + 2 + e−2x 4 − = 4 = . (b) we start with the identity proved in part (a): cosh2(x) − sinh2(x) = 1. if we divide both sides by cosh2(x), we get 1 − sinh2(x) cosh2(x) = 1 or 1 − tanh 2(x) = .