A baseball is hit with an initial vertical velocity of 121 feet per second and the ball was hit 1 foot above ground. How high is the ball after 4 seconds? h = −16t^2 + 121t + 1

After 4 seconds, the ball is at 229 ft

Step-by-step explanation:

Here, we want to get the height of the ball at 4 seconds

What we have to do here is to substitute the value of t for 4 seconds in the equation

We have;

h = -16(4^2) + 121(4) + 1

h = -256 + 484 + 1

h = 229 ft

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